
CH 2 Handout review | page 7 | https://thedailydialectics.com/pdfs/education/calculus/calculus-2-2413-HCC/CH 2 Handout review/CH 2 Handout review.pdf
I y= x _ xl/2 2x2-4 2x2-4 u(x) = x1/2 > u'(x) = oe? > v(x) = 2x2 -4 > v'(x) = 4x 1-1/2 (22 ~ 4) - 4x(x1/2) §'0) <2 _ x3/2— 2x -1/2 ~ 43/2 (2x2 - 4)2 (2x2 - 4)? _ ~3x3/2 — 2x -1/2 (2x2 - 4)? The Tangent and Cotangent Functions Rules 4 tan x| =sec2x ; A foot x| =-cesc2 x dx dx The Secant and Cosecant…